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The density of helium is 0.1784 kg/m3 at STP. If a given mass of helium at STP is allowed to expand to 1.400 times of its initial volume by changing P and T, compute its resultant density. |
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Answer» Given w/v = 0.1784 kg/m3 = 0.1784 g/litre at STP It means 1 litre of gas at STP occupies 0.1784 g weight Now by changing P the V becomes 1.4 x l litre, where weight remains same. Thus, d = w/v = 0.1784/1.4 = 0.1274 kg/m3 = 0.1274 g/litre. |
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