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The ascending order of $(2.89)^{0.5}$ ,$2-(0.5)^{2}$ , $\sqrt{3}$ and $\sqrt[3]{0.008}$ is :1). $2-(0.5)^{2}$ , $\sqrt{3}$ and $\sqrt[3]{0.008}$,$(2.89)^{0.5}$2). $\sqrt[3]{0.008}$,$(2.89)^{0.5}$,$\sqrt{3}$,$2-(0.5)^{2}$3). $\sqrt[3]{0.008}$,$\sqrt{3}$,$(2.89)^{0.5}$ ,$2-(0.5)^{2}$4). $\sqrt{3}$ and $\sqrt[3]{0.008}$,$2-(0.5)^{2}$,$(2.89)^{0.5}$

Answer» CORRECT ANSWER is: $\SQRT[3]{0.008}$,$(2.89)^{0.5}$,$\sqrt{3}$,$2-(0.5)^{2}$


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