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The angular velocity and amplitude of simple pendulum are `omega` and r respectively. At a displacement x from the mean position, if its kinetice energy is T and potential energy is U, find the ration of T to U. |
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Answer» Kinetice energy, `T=(1)/(2)mU^(2)=(1)/(2)momega^(2)(r^(2)-x^(2)),` Potential energy, `U=(1)/(2)momega^(2)x^(2),` so `(T)/(U)=(r^(2)-x^(2))/(x^(2))` |
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