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Solve: `(2x-3)/(3x-7)gt0,x in R` |
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Answer» Correct Answer - `(-oo,(3)/(2))uu((7)/(3),oo)` `(2x-3lt0and3x-7lt0)or(2x-3gt0and3x-7gt0)` `rArr (xlt(3)/(2)andxlt(7)/(3))or(xgt(3)/(2)andxgt(7)/(3))` `rArr(xlt(3)/(2))or(xgt(7)/(3))rArr x in(-oo,(3)/(2))uu((7)/(3),oo)`. |
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