Saved Bookmarks
| 1. |
Show that `f(x)=|x|`is not differentiable at `x=0.` |
|
Answer» `f(x)=|x|` `lim_(h->0) (f(x+h)-f(x))/h` `LHL=RHL` `LHL` when `x<0 , x=0` `f(x)=-x` `lim_(h->0) (f(0+h)-f(0))/h ` `=(-h-0)/h` `=-1` `RHL` when`x>0` `lim_(h->0) (f(0+h)-f(0))/h` `=(h+0)/h=1` `LHL=-1,RHL=1` `LHL&RHL`Both exits but not equal `LHL!=RHL` |
|