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If y = mx + c and f(0) = f'(0) = 1, then f(2) is …(a) 1 (b) 2 (c) 3 (d) -3 |
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Answer» (c) 3 y = mx + c dy/dx = m y = x + c (i.e.) f(x) = x + c y(at x = 0) = f(0) 0 + c = 1 ⇒ c = 1 y = x + 1 ⇒ f(x) = x + 1 f(2) = 2 + 1 = 3 |
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