1.

If y = mx + c and f(0) = f'(0) = 1, then f(2) is …(a) 1 (b) 2 (c) 3 (d) -3

Answer»

(c) 3 

y = mx + c 

dy/dx = m 

y = x + c (i.e.) f(x) = x + c 

y(at x = 0) = f(0) 0 + c = 1 ⇒ c = 1 

y = x + 1 ⇒ f(x) = x + 1 

f(2) = 2 + 1 = 3



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