1.

Quantity B: A cycle can travel at an average speed of 6 km/hr, and complete the journey on time. If the average speed of the cycle becomes 4 km/hr then it completes the journey 12 minutes late. Find the distance of the journey.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B

Answer»

Quantity A:

TOTAL distance travelled by cycle in 4 hours is –

Distance COVERED by cycle in the first hour = 10 km

Distance travelled in second hour = 7 km

Distance travelled in third hour = 4 km

Distance travelled in forth hour = 1 km

Total distance covered by cycle in 4 hours =

= 10 + 7 + 4 + 1

= 22

Total distance travelled by cycle in 4 hours is 22 km.

Quantity B:

Difference between the time travelled by cycle = 12 min = 12/60h = 1/5h

Let the length of journey be a km.

Then,

(a/4) – (a/6) = 1/5

2a/24 = 1/5

a = 12/5 = 2.4 kms

Total journey is 2.4 kms

From above solution,

RELATION between Quantity A > Quantity B is ESTABLISHED.


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