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Quantity B: A cycle can travel at an average speed of 6 km/hr, and complete the journey on time. If the average speed of the cycle becomes 4 km/hr then it completes the journey 12 minutes late. Find the distance of the journey.1). Quantity A > Quantity B2). Quantity A < Quantity B3). Quantity A ≥ Quantity B4). Quantity A ≤ Quantity B |
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Answer» Quantity A: TOTAL distance travelled by cycle in 4 hours is – Distance COVERED by cycle in the first hour = 10 km Distance travelled in second hour = 7 km Distance travelled in third hour = 4 km Distance travelled in forth hour = 1 km Total distance covered by cycle in 4 hours = = 10 + 7 + 4 + 1 = 22 Total distance travelled by cycle in 4 hours is 22 km. Quantity B: Difference between the time travelled by cycle = 12 min = 12/60h = 1/5h Let the length of journey be a km. Then, (a/4) – (a/6) = 1/5 2a/24 = 1/5 a = 12/5 = 2.4 kms Total journey is 2.4 kms From above solution, RELATION between Quantity A > Quantity B is ESTABLISHED. |
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