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Quantity B: 1001). Quantity A > Quantity B2). Quantity A ≥ Quantity B3). Quantity B > Quantity A4). Quantity B ≥ Quantity A |
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Answer» QUANTITY A: Total distance traveled = 200 × 5 + 100 × 10 + 50 × 2 + 25 × 5 km ⇒ 1000 + 1000 + 100 + 125 km = 2225 km Total TIME = 5 + 10 + 2 + 5 = 22 hours Required speed = 2225/22 = 101.14 kmph Quantity B: 100 ∴ Quantity A > Quantity B |
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