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Purple of Cassius is obtained by the addition of `SnCl_(2)` solution to a solution ofA. `CuCl_(2)`B. `HgCl_(2)`C. `Hg_(2)Cl_(2)`D. `AuCl_(3)` |
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Answer» Correct Answer - D `2Au^(3+)+3Sn^(2+)rarr2Au+3Sn^(4+)`. Au is adsorbed over `Sn(OH)_(4)` formed giving purple of Cassius. |
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