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Prove that `tan x gt x` for all `x in [0, (pi)/(2)]`

Answer» Let c be an arbitrary real number such that `c in [0, (pi)/(2)]`
Let f(x) `= tan x - x` for all `x in [0, c]`
`:. F(x) = sec^(2) x - 1 = tan^(2) x gt 0` for all `x in [0, c]`
Thus, f(x) is increasing on [0, c]
Now, `x gt 0 rArr f(x) gt f(0)`
`rArr f(x) gt0`
`rArr tan x - x gt 0`
`rArr tan x gt x`


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