Saved Bookmarks
| 1. |
One mole of an ideal monoatomic gas is taken at a temperature of `300 K`. Its volume is doubled keeping its pressure constant. Find the change in internal energy. |
|
Answer» Since, pressure is constant `therefore" " VpropTtherefore(V_(i))/T_(i)=(V_(f))/T_(f)` `therefore" " T_(f)=(V _(f))/V_(i)TirArrT_(f)=2T_(i)=600K` `therefore" " DeltaU=f/2n.RDeltaT=3/2R(600-300)=450R` |
|