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One end of a taut string of length `3m` along the x-axis is fixed at `x = 0`. The speed of the waves in the string is `100ms^(-1)`. The other end of the string is vibrating in the y-direction so that stationary waves are set up in the string. The possible wavelength`(s)` of these sationary waves is (are)A. `y(t)=Asin((pix)/(6))cos((50pit)/(3))`B. `y(t)=Asin((pix)/(3))cos((100pit)/(3))`C. `y(t)=Asin((5pix)/(6))cos((250pit)/(3))`D. `y(t)=Asin((5pix)/(6))cos250pit` |
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Answer» Correct Answer - A::C::D There will be a node at `x=0` and antinode at `x=3` .Here, `upsilon=(omega)/(k)=100m//s.` Hence, at `x=0,y=0` and at`x=3cm,y=+A.` The above conditions are satisfied in options (a), (c) and (d). |
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