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Maximum velocity of a particle in SHM is `16cm^(-1)` . What is the average velocity during motion from one extreme position to other extreme position? |
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Answer» Given, Max. velocity `=aomega=16cms^(-1)` or `a(2pi)/(T)=16 or (a)/(T)=(1)/(2pi)` Average velocity, `v_(av)=(t otal displacement)/(t otal ti me)=(2a)/(T//2)=(4a)/(T)` `:.v_(av)=4xx(16)/(2pi)=(32)/(pi)cms^(-1)`. |
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