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Maximum velocity of a particle in SHM is 10 cm`//`s . What is the average velocity during motion from one extreme position to other extreme position ? |
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Answer» Max. velocity, `v_(m)=aomega=a 2pi//T` …(i) Average velocity `=(t otal displacement)/(t otal time)` `:. v_(av)=(2a)/(T//2)=(4a)/(t)=4((v_(m))/(2pi))` [from (i)] `=(2v_(m))/(pi)=(2xx10)/(pi)=(20)/(pi)cm//s` |
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