1.

Maximum velocity of a particle in SHM is 10 cm`//`s . What is the average velocity during motion from one extreme position to other extreme position ?

Answer» Max. velocity, `v_(m)=aomega=a 2pi//T` …(i)
Average velocity `=(t otal displacement)/(t otal time)`
`:. v_(av)=(2a)/(T//2)=(4a)/(t)=4((v_(m))/(2pi))` [from (i)]
`=(2v_(m))/(pi)=(2xx10)/(pi)=(20)/(pi)cm//s`


Discussion

No Comment Found

Related InterviewSolutions