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`lim_(xtooo) x sin"" 1/x` का मान ज्ञात कीजिये। |
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Answer» `underset(xtooo)lim x sin ""1/x=underset(x to oo)lim (sin (1//2))/(1//x)` माना `1/x=theta` अतः यदि `x=oo` तब `theta=0` `therefore x to ooimpliestheta to 0` `therefore underset(xtooo)lim (sin 1//x)/((1//x))=underset(xto0)lim(sin theta)/(theta)=1` |
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