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`lim_(xto1) ((2x-3)(sqrtx-1))/(3x^(2)+3x-6)` का मान गये कीजिये। |
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Answer» `underset(x to 1)lim((2x-3)(sqrtx-1))/(3x^(2)+3x-6)=underset(xto1)lim((2x-3)(sqrtx-1)(sqrtx+1))/(3(x^(2)+x-2)(sqrtx+1))` `=underset(xto1)lim((2x-3))/(3(x+2)(x-1))((x-1)/(sqrtx+1))` `=underset(xto1)lim ((2x-3))/(3(x+2)(sqrtx+1))=(-1)/(18)` |
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