1.

Let ν1 be the frequency of the series limit of the Lyman series, ν2 be the frequency of the first line of the Lyman series, and ν3 be the frequency of the series limit of the Balmer series. (a) ν1 - ν2 = ν3 (b) ν2 - ν1 = ν3 (c) ν3 = 1/2 (ν1 + ν2) (d) ν1 + ν2 = ν3

Answer»

Correct Answer is: (a) ν1 - ν2 = ν3 

Series limit means the shortest possible wavelength (maximum photon energy), and first line means the longest possible wavelength (minimum photon energy) in the series.

ν = c [1/n2 - 1/m2], where c = constant.

For series limit of the Lyman series, n = 1, m = , ν1 = c.

For first line of the Lyman series, n = 1, m = 2, ν2 = 3c/4 .

For series limit of the Balmer series, n = 2, m  , ν3 = c/4.

 ∴ ν1 - ν2 = ν3.



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