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Incorrect StatementA. `SnCl_(2)` reduces Nitrobenzene to anilineB. `SnCl_(2)` reduces gold chloride `(AuCl_(3))` to metallic gold sol ( purple of cassius)C. When `SnCl_(2)` is treated with excess of `NaOH` an insoluble `Sn(OH)_(2)` which precipitate is formed.D. When `SnCl_(2)` reacts with conc. `HCL,` chlorostannic acid `H_(2)SnCl_(6)` is formed. |
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Answer» Correct Answer - C `SnCl_(2)+NaOHrarrSn(OH)_(2)darr` `SnCl_(2)+underset(("excess"))(NaOH)rarrNa_(2)SnO_(2)("soluble")` |
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