Saved Bookmarks
| 1. |
In the given questions, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answerI. 12x2 – 46x + 14 = 0II. 14y2 – 46y + 12 = 01. x > y2. x ≤ y3. x = y or the relationship cannot be established.4. x ≥ y5. x < y |
|||||||||||||||
|
Answer» Correct Answer - Option 3 : x = y or the relationship cannot be established. I. 12x2 – 46x + 14 = 0 ⇒ 12x2 – 42x – 4x + 14 = 0 ⇒ 6x(2x – 7) – 2(2x – 7) = 0 ⇒ (2x – 7)(6x – 2) = 0 ⇒ x = 7/2 or 1/3 II. 14y2 – 46y + 12 = 0 ⇒ 14y2 – 42y - 4y + 12 = 0 ⇒ 14y(y – 3) – 4(y – 3) = 0 ⇒ (y – 3) × (14y – 4) = 0 ⇒ y = 3 or 2/7 Comparison between x and y (via Tabulation):
∴ The relationship cannot be established between x and y. |
||||||||||||||||