1.

In the given questions, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answerI. 8x2 – 32x + 14 = 0II. 3y2 – 37y – 26 = 01.x &gt; y2. x ≤ y3. x = y or the relationship cannot be established.4. x ≥ y5. x < y

Answer» Correct Answer - Option 3 : x = y or the relationship cannot be established.

I. 8x2 – 32x + 14 = 0

⇒ 8x2 – 28x – 4x + 14 = 0

⇒ 4x(2x – 7) – 2(2x – 7) = 0

⇒ (2x – 7)(4x – 2) = 0

⇒ x = 7/2 or 1/2

II. 3y2 – 37y – 26 = 0

⇒ 3y2 – 39y + 2y – 26 = 0

⇒ 3y(y – 13) + 2(y – 13) = 0

⇒ (y – 13)(3y + 2) = 0

⇒ y = 13 or -(2/3)

Comparison between x and y (via Tabulation):

Value of x

Relation

Value of y

7/2

< 

13

7/2

> 

-(2/3)

1/2

< 

13

1/2

> 

-(2/3)

∴ Relationship cannot be established between x and y.


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