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In the given questions, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answerI. x2 + x – 56 = 0II. y2 – 23y + 132 = 01. x > y2. x ≥ y3. x < y4. x ≤ y5. x = y or the relationship cannot be established |
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Answer» Correct Answer - Option 3 : x < y Given: I. x2 + x – 56 = 0 II. y2 – 23y + 132 = 0 Calculation: I. x2 + x – 56 = 0 ⇒ x2 + 8x – 7x – 56 = 0 ⇒ x(x + 8) – 7(x – 8) = 0 ⇒ (x + 8)(x – 7) = 0 Then, x = – 8 or x = 7 Now, II. y2 – 23y + 132 = 0 ⇒ y2 – 12y – 11y + 132 = 0 ⇒ y(y – 12) – 11(y – 12) = 0 ⇒ (y – 12)(y – 11) = 0 Then, y = 12 or y = 11 Now, Comparison between x and y (via Tabulation):
∴ We can clearly see that x < y |
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