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In the figure, O is the centre of the circle. Seg AC is the diameter `/_ ABC` is inscribed in arc ABC and intercepts arc AMC then prove `/_ ABC = 90^(@)` |
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Answer» Proof `:` m (arc AMC ) `= 180^(@)` …(Measure of a semicircle is `180^(@)`) …(1) `/_ABC = (1)/(2) `m (arc AMC ) …(Inscribed angle theorem ) `:. /_ ABC = (1)/(2) xx 180^(@)` ….[From (1) ] `:. /_ABC = 90^(@)` |
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