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In the figure below, ∠DEC+∠BFC is equal to _______...
1.
In the figure below, ∠DEC+∠BFC is equal to _______ .(A) ∠ BCD – ∠ BAD(B) ∠ BAD + ∠ BCF(C) ∠ BAD + ∠ BCD(D) ∠ CBA + ∠ ADC
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