Related InterviewSolutions

• In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the complete solution of current.(a) i = e^-37.5t(c1cos1290t + c2sin1290t) + 0.7cos(500t + π/4 + 88.5⁰)(b) i = e^-37.5t(c1cos1290t + c2sin1290t) + 0.7cos(500t – π/4 + 88.5⁰)(c) i = e^-37.5t(c1cos1290t + c2sin1290t) – 0.7cos(500t – π/4 + 88.5⁰)(d) i = e^-37.5t(c1cos1290t + c2sin1290t) – 0.7cos(500t + π/4 + 88.5⁰)I have been asked this question during a job interview.This key question is from Sinusoidal Response of an R-L-C Circuit in portion Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the particular solution.(a) ip = 0.6cos(500t + π/4 + 88.5⁰)(b) ip = 0.6cos(500t + π/4 + 89.5⁰)(c) ip = 0.7cos(500t + π/4 + 89.5⁰)(d) ip = 0.7cos(500t + π/4 + 88.5⁰)I got this question in unit test.Enquiry is from Sinusoidal Response of an R-L-C Circuit topic in section Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the roots of the characteristic equation.(a) -38.5±j1290(b) 38.5±j1290(c) 37.5±j1290(d) -37.5±j1290The question was posed to me during an online interview.This interesting question is from Sinusoidal Response of an R-L-C Circuit in section Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0. Applied voltage is v (t) = 400cos (500t + π/4). Resistance R = 15Ω, inductance L = 0.2H and capacitance = 3 µF. Find the complementary current.(a) ic = e^-37.5t(c1cos1290t + c2sin1290t)(b) ic = e^-37.5t(c1cos1290t – c2sin1290t)(c) ic = e^37.5t(c1cos1290t – c2sin1290t)(d) ic = e^37.5t(c1cos1290t + c2sin1290t)I got this question in class test.This is a very interesting question from Sinusoidal Response of an R-L-C Circuit in chapter Transients of Network Theory
• In the sinusoidal response of R-L-C circuit, the complementary function of the solution of i is?(a) ic = c1 e^(K1+K2)t + c1 e^(K1-K2)t(b) ic = c1 e^(K1-K2)t + c1 e^(K1-K2)t(c) ic = c1 e^(K1+K2)t + c1 e^(K2-K1)t(d) ic = c1 e^(K1+K2)t + c1 e^(K1+K2)tI have been asked this question in an interview for internship.My question is taken from Sinusoidal Response of an R-L-C Circuit in chapter Transients of Network Theory
• The complete solution of the current in the sinusoidal response of R-L-C circuit is?(a) i = c1 e^(K1+K2)t + c1 e^(K1-K2)t – V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC-ωL)/R))(b) i = c1 e^(K1+K2)t + c1 e^(K1-K2)t– V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ-tan^-1)⁡((1/ωC-ωL)/R))(c) i = c1 e^(K1+K2)t + c1 e^(K1-K2)t + V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC-ωL)/R))(d) i = c1 e^(K1+K2)t + c1 e^(K1-K2)t+ V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ-tan^-1)⁡((1/ωC-ωL)/R))The question was asked in final exam.My question comes from Sinusoidal Response of an R-L-C Circuit topic in division Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The complete solution of ‘i’ is?(a) i = [(3.53-4.99×10^-3)cos⁡(π/4+89.94^o)] exp⁡(-t/0.00001)+4.99×10^-3)cos⁡(100t+π/2+89.94^o)(b) i = [(3.53+4.99×10^-3)cos⁡(π/4+89.94^o)] exp⁡(-t/0.00001)+4.99×10^-3)cos⁡(100t+π/2+89.94^o)(c) i = [(3.53+4.99×10^-3)cos⁡(π/4+89.94^o)] exp⁡(-t/0.00001)-4.99×10^-3)cos⁡(100t+π/2+89.94^o)(d) i = [(3.53-4.99×10^-3)cos⁡(π/4+89.94^o)] exp⁡(-t/0.00001)-4.99×10^-3)cos⁡(100t+π/2+89.94^o)The question was asked by my college professor while I was bunking the class.I need to ask this question from Sinusoidal Response of an R-C Circuit topic in division Transients of Network Theory
• The particular current obtained from the solution of i in the sinusoidal response of R-L-C circuit is?(a) ip = V/√(R^2+(1/ωC+ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC+ωL)/R))(b) ip = V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC-ωL)/R))(c) ip = V/√(R^2+(1/ωC+ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC-ωL)/R))(d) ip = V/√(R^2+(1/ωC-ωL)^2) cos⁡(ωt+θ+tan^-1)⁡((1/ωC+ωL)/R))The question was posed to me in unit test.My doubt stems from Sinusoidal Response of an R-L-C Circuit in portion Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The value of c in the complementary function of ‘i’ is?(a) c = (3.53-4.99×10^-3) cos⁡(π/4+89.94^o)(b) c = (3.53+4.99×10^-3) cos⁡(π/4+89.94^o)(c) c = (3.53+4.99×10^-3) cos⁡(π/4-89.94^o)(d) c = (3.53-4.99×10^-3) cos⁡(π/4-89.94^o)I had been asked this question in a national level competition.My question comes from Sinusoidal Response of an R-C Circuit in section Transients of Network Theory
• In the circuit shown below, the switch is closed at t = 0, applied voltage is v (t) = 50cos (102t+π/4), resistance R = 10Ω and capacitance C = 1µF. The complete solution of ‘i’ is?(a) i = c exp (-t/10^-5) – (4.99×10^-3) cos⁡(100t+π/2+89.94^o)(b) i = c exp (-t/10^-5) + (4.99×10^-3) cos⁡(100t+π/2+89.94^o)(c) i = -c exp(-t/10^-5) + (4.99×10^-3) cos⁡(100t+π/2+89.94^o)(d) i = -c exp(-t/10^-5) – (4.99×10^-3) cos⁡(100t+π/2+89.94^o)The question was asked in an online interview.I'm obligated to ask this question of Sinusoidal Response of an R-C Circuit topic in division Transients of Network Theory