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If `y = x^(2) " sin " (1)/(x) " then " (dy)/(dx) =` ?A. `x "sin " (1)/(x) - " cos " (1)/(x)`B. `-"cos "(1)/(x) + 2x "sin " (1)/(x)`C. `-x " sin " (1)/(x) + " cos"(1)/(x)`D. none of these |
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Answer» Correct Answer - B `(dy)/(dx) = x^(2).("cos"(1)/(x)) ((-1)/(x^(2))) + 2x "sin " (1)/(x)` |
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