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If `y = sec^(-1) ((x^(2) + 1)/(x^(2) -1)) " then " (dy)/(dx) =` ?A. `(-2)/((1 + x^(2)))`B. `(2)/((1 + X^(2)))`C. `(-1)/((1 - X^(2)))`D. none of these

Answer» Correct Answer - A
Put `x = cot theta`. Then, `y = sec^(-1) ((1 + tan^(2) theta)/(1 - tan^(2) theta)) = sec^(-1) ((1)/(cos 2 theta)) = sec^(-1) (sec 2 theta) = 2 theta = 2 cot^(-1) x`


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