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If `y = sec^(-1) ((1)/(2x^(2) -1)) " then " (dy)/(dx)`= ?A. `(-2)/((1 + x^(2)))`B. `(-2)/((1 -x^(2)))`C. `(-2)/(sqrt(1 -x^(2)))`D. none of these

Answer» Correct Answer - C
Put `x = cot theta`. Then, `y = sec^(-1) ((1)/(2 cos^(2) theta -1)) = sec^(-1) (sec 2 theta) = 2 theta = 2 cos^(-1) x`


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