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If `y = e^(x) + e^(x + ...oo) " then " (dy)/(dx)=` ?A. `(1)/((1-y))`B. `(y)/((1 -y))`C. `(y)/((y -1))`D. none of these |
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Answer» Correct Answer - B `y = e^(x + y) rArr x + y = log y rArr 1 + (dy)/(dx) = (1)/(y) .(dy)/(dx)` |
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