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If `y = cot^(-1) ((1 -x)/(1 +x)) " then " (dy)/(dx) =` ?A. `(-1)/((1 +x^(2)))`B. `(1)/((1 + x^(2)))`C. `(1)/((1 + x^(2))^(.^(3)//_(2)))`D. none of these

Answer» Correct Answer - B
Put `x = tan theta`, They, `y = cot^(-1) .tan ((pi)/(4) - theta) = cot^(-1) [cot {(pi)/(2) - ((pi)/(4) - theta)}] = ((pi)/(4) + theta)`
`:. y = (pi)/(4) + tan^(-1) x`


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