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If `y = cos^(-1) (4x^(3) -3x) " then " (dy)/(dx)=` ?A. `(3)/(sqrt(1 -x^(2)))`B. `(-3)/(sqrt(1 -x^(2)))`C. `(4)/(sqrt(1 -x^(2)))`D. `(-4)/((3x^(2) -1))` |
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Answer» Correct Answer - B Putting `x = cos theta`, we get `y = cos^(-1) (cos 3 theta) = 3 theta = 3 cos^(-1) x` |
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