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If `x = a sec theta, y = b tan theta " then " (dy)/(dx) =` ?A. `(b)/(a) sec theta`B. `(b)/(a) "cosec" theta`C. `(b)/(a) cot theta`D. none of these

Answer» Correct Answer - B
`(dx)/(d theta) = a sec theta tan theta, (dy)/(d theta) = b sec^(2) theta .(dy)/(dx) = ((.^(dy)//_(d theta)))/((.^(dx)//_(d theta))) = (b)/(a) " cosec " theta`


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