Saved Bookmarks
| 1. |
If `x = a cos^(2) theta, y = b sin^(2) theta " then "(dy)/(dx)=` ?A. `(-a)/(b)`B. `(a)/(b) cot theta`C. `(-b)/(a)`D. none of these |
|
Answer» Correct Answer - C `(dx)/(d theta) = - 2 a cos theta sin theta, (dy)/(d theta) = 2b sin theta cos theta rArr (dy)/(dx) = ((.^(dy)//_(d theta)))/((.^(dx)//_(d theta))) = (-b)/(a)` |
|