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If the radius of asphere is measured as 9 cm with an error or 0.03 m, find the approximateerror in calculating its surface area. |
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Answer» Let r be the radius and S be the total surface area of the sphere. Given ` r = 9 m and Delta r = 0.03 cm` Now ` S = 4pi r^(2)` ` rArr (dS)/(dr) = 8 pi r` `:. Delta S = (dS)/(dr) * Delta r = 8 pi r * Dleta r` ` = 8 pi xx 900 xx 0.03 cm^(2)` ` = 216 pi cm^(2)` |
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