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If `int_0^1(e^t)/(1+t)dt=a ,`then find the value of `int_0^1(e^t)/((1+t)^2)dt`in terms of `a`. |
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Answer» Correct Answer - `a+1-e/2` `a=int_(0)^(1)(e^(t))/(1+t)dt=(1/((1+t))e^(t))_(0)^(1)=int_(0)^(1)(e^(t))/((1+t)^(2))dt` (Integrating by parts) `=e/2-1+int_(0)^(1)(e^(t))/((1+t)^(2)) dt` or `int_(0)^(1) (e^(t))/((1+t)^(2))dt=a+1-e/2` |
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