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If [H2]t=0.10 M, [I2]t = 0.20 M and [HI]t = 0.40 M, in the reaction H2(g) + I2(g) \(\rightleftharpoons\) 2HI(g), what is the value of QC?(a) 8(b) 4(c) 2(d) 1The question was posed to me in my homework.This intriguing question originated from Applications of Equilibrium Constants topic in division Equilibrium of Chemistry – Class 11 |
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Answer» CORRECT ANSWER is (a) 8 The best explanation: We know that reaction quotient Qc = [HI]t^2 / [H2]t[I2]t and given that [H2]t=0.10 M, [I2]t = 0.20 M and [HI]t = 0.40 M, So by substituting, we GET Qc = (0.40 M x 0.40 M)/(0.20 M x 0.10 M) = 8.0, 8 is the answer. |
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