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If `|AxxB| = sqrt3 A.B,` then the value of |A+B| isA. `(A^(2)+B^(2)+(AB)/(sqrt(3)))^(1//2)`B. `A+B`C. `(A^(2)+B^(2)+sqrt(3)AB)^(1//2)`D. `(A^(2)+B^(2)+AB)^(1//2)` |
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Answer» Correct Answer - D (d) `ABsintheta=sqrt(3)ABcosthetaortantheta=sqrt(3)` `:.theta=60^(@)` Now `|A+B|=sqrt(A^(2)+B^(2)+2ABcos60^(@))` `=sqrt(A^(2)+B^(2)AB)` |
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