for the reaction H2(g) + Br2(g) ↔ 2HBr(g) the equilibrium constant is given as 0.04 then what is the equilibrium constant for the reaction 2HBr(g) ↔ H2(g) + Br2(g)?(a) 0.04(b) 4(c) 25(d) 100The question was posed to me in homework.My question comes from Law of Chemical Equilibrium and Equilibrium Constant topic in chapter Equilibrium of Chemistry – Class 11

for the reaction H2(g) + Br2(g) ↔ 2HBr(g) the equilibrium constant i

1.	for the reaction H2(g) + Br2(g) ↔ 2HBr(g) the equilibrium constant is given as 0.04 then what is the equilibrium constant for the reaction 2HBr(g) ↔ H2(g) + Br2(g)?(a) 0.04(b) 4(c) 25(d) 100The question was posed to me in homework.My question comes from Law of Chemical Equilibrium and Equilibrium Constant topic in chapter Equilibrium of Chemistry – Class 11
Answer» Right answer is (C) 25 The explanation: In a chemical REACTION if the equilibrium CONSTANT for a backward reaction is given by K then the equilibrium constant for the forward reaction is given by 1/k, so your the resultant answer becomes 1/0.04 = 25.

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