1.

Find the slope of the tangent to the curve `y=x^3-3x+2` at the point whose x-coordinate is 3.

Answer» `y = x^(3)- 3x + 2`
` rArr (dy)/(dx) = 3x^(2)-3`
at x = 3
Slope of tangent
`m = 3 (3)^(2) - 3 = 24`


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