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Find the slope of the tangent to the curve `y=(x-1)/(x-2), x!=2`at `x= 10`. |
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Answer» `y = (x-1)/(x-2)` ` rArr (dy)/(dx) = ((x-2)d/(dx)(x-1)-(x-1)d/(dx)(x-2))/((x-2)^(2))` ` = ((x-2)-(x-1))/((x-2)^(2))=(-1)/((x-2)^(2))` at x = 10 Slope of tangent ` m = (-1)/((10-2)^(2)) =-1/64` |
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