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Find the maximum and minimum values of `f(x) = (-x + 2sin x) " on " [0, 2pi]`

Answer» Correct Answer - max. value is `(-(pi)/(3) + sqrt3) " at " x = (pi)/(3)` and min. value is `((5pi)/(3) + sqrt3) " at " x = (5pi)/(3)`


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