Find the general solution of the differential equations `sec^2xtany dx – InterviewSolution

1.	Find the general solution of the differential equations `sec^2xtany dx+sec^2ytanx dy=0`
Answer» Correct Answer - `tan y = C (1-e^(x))` `int (sec^(2)x)/(tanx) dx +int (sec^(2)y)/(tany) dy = log \|C_(1)\|rArr log \|tanx\|+log \|tan y\| = log \|C_(1)\|` `therefore log \|tan x tany\| = log \|C_(1)\| rArr \|tan x tany\|=\|C_(1)\|.` `therefore tanx tan y = pm C_(1) = C.`

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