Find the equation of the normal to the curve `x^2=4y`which passes thro

1.	Find the equation of the normal to the curve `x^2=4y`which passes through the point (1, 2).
Answer» Equation of given curve is : `y^(2) = 4x` ` rArr 2y(dy)/(dx) = 4 rArr (dy)/(dx) = 4/(2y) = 2/y` `:." slope of tangent at point "(1, 2) is ((dy)/(dx))_(1, 2) = 2/2 = 1` Slope of normal at point `(1, 2), = - 1/1 =- 1` ` :. ` equation of normal at point (1, 2), ` y-2 =- 1(x-1)` ` rArr y-2=-x+1 rArr x+y-3=0`

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Find the equation of the normal to the curve `x^2=4y`which passes through the point (1, 2).

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