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Find the equation of tangent of tangent of the curve y = `b * e^(-x//a)` at that point at which the curve meets the Y-axis. |
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Answer» `y=b*e^(-x//a) …(1)` At Y-axis, x=0 `:. Y=be^(0)= b` So, we will find the equation of tantion of tangent at point (0, b). Now differentiare eq. (1) with respect to x. `(dy)/(dx) =-b/a * e^(-x//a)` Slope of tnagent at point (0, b) is `m =-b/a * e^(0)=-b/a` and equation of tangent ` y-b=-b/a*(x-0)` `rArr ay - ab=-bx` `rArr bx + ay = ab`. |
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