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Find the equation of all lines having slope 2 which are tangents to the curve `y=1/(x-3), x!=3` |
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Answer» Slope of tangent = 2 Equation of curve ` y = 1/(x-3)` `rArr (dy)/(dx) = (-1)/((x-3)^(2))` Slope of tangent at point `(x, y) = (-1)/((x-3)^(2))` `:. (-1)/((x-3)^(2)) = 2` ` rArr (x-3)^(2) = - 1/2` which is impossible. Therefore, there is no tangent of the given curve with slope 2. |
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