Saved Bookmarks
| 1. |
Find the displacement of a simple harmonic oscillator at which its P.E. is half of the maximum energy of the oscillator. |
|
Answer» Let at an instatn the displacement of the particle from the mean position be y. Then its PE is `E_(P)=(1)/(2)momega^(2)y^(2)` Total energy, `E=(1)/(2)momega^(2)r^(2)` As per question, `PE=(1)/(2)xxTE` `:.(1)/(2)momega^(2)y^(2)=(1)/(2)xx(1)/(2)momega^(2)r^(2) or y^(2)=(r^(2))/(2) or y=+-(r)/(sqrt(2))` |
|