1.

Find the dimension of the rectangle of area `96 cm^(2)` whose perimeter is the least, Also, find the perimeter of the rectangle

Answer» Correct Answer - length = `4 sqrt6 cm`, breadth `= 4 sqrt6 cm`, perimeter `= 16 sqrt6 cm`
Let P be the fixed perimeter and x, y be the sides
Then, `96 = xy rArr y = (96)/(x)`
`P = 2 (x + y) rArr P = 2 (x + (96)/(x))`
`P = 2(x + y) rArr y = (1)/(2) (P - 2x) " " :. A = xy rArr A = (1)/(2) x (P - 2x)`


Discussion

No Comment Found

Related InterviewSolutions