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`CuSO_(4)` solution reacts with excess of KCN solution to form:-A. `[Cu(CN)_(4)]^(2-)`B. `[Cu(CN)_(4)]^(3-)`C. `Cu(CN)_(2)`D. `Cu_(2)(CN)_(2)` |
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Answer» Correct Answer - B `2CuSO_(4)+10KCNrarr2K_(3)[Cu(CN)_(4)]+(CN)_(2)+2K_(2)SO_(4)` |
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