Copper sulphate is prepared by blowing a current of air through copper scrap and dilute `H_(2)SO_(4)`. Dilute `HNO_(3)` is also added`:`A. to oxidise copper to `Cu^(2+)` which then form `CuSO_(4)` with dilute `H_(2)SO_(4)`B. to oxidise `Fe^(2+)` to iron `(III)` sulphate, which remains in solution after crystallisation of `CuSO_(4)`C. to speed up the ionisation of `H_(2)SO_(4)` to give `SO_(4)^(2-)` ionsD. which combines with `H_(2)SO_(4)` to give a very strong oxidising mixture and oxidise Cu to `Cu^(2+)`

Copper sulphate is prepared by blowing a current of air through copper

1.	Copper sulphate is prepared by blowing a current of air through copper scrap and dilute `H_(2)SO_(4)`. Dilute `HNO_(3)` is also added`:`A. to oxidise copper to `Cu^(2+)` which then form `CuSO_(4)` with dilute `H_(2)SO_(4)`B. to oxidise `Fe^(2+)` to iron `(III)` sulphate, which remains in solution after crystallisation of `CuSO_(4)`C. to speed up the ionisation of `H_(2)SO_(4)` to give `SO_(4)^(2-)` ionsD. which combines with `H_(2)SO_(4)` to give a very strong oxidising mixture and oxidise Cu to `Cu^(2+)`
Answer» Correct Answer - A `Fe(OH)_(3) & Al(OH)_(3)` can be separated by NaOH

Discussion

No Comment Found

Related InterviewSolutions

A compound (A) is greenish crystalline salt which gave the following results `:` `i)` Addition of `BaCl_(2)` solution to solution of (A) results in the formation of a white ppt. (B), which is insoluble in dil. HCl. `ii)` On heating (A), water vapours and two oxides of sulphur, (C ) and (D) are liberated leaving a red brown residue (E). `iii)` (E) dissolves in warm conc. HCl to give a yellow solution (F). `iv)` With `H_(2)S`, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H). `v)` Solution (F) on treatment with thiocyanate ions gives blood red coloured compound (I). Identify the substances from (A) to (I). Yellow ppt (G) is a `:`A. Solution (F)B. Solution (H)C. A and B bothD. None of these
A compound (A) is greenish crystalline salt which gave the following results `:` `i)` Addition of `BaCl_(2)` solution to solution of (A) results in the formation of a white ppt. (B), which is insoluble in dil. HCl. `ii)` On heating (A), water vapours and two oxides of sulphur, (C ) and (D) are liberated leaving a red brown residue (E). `iii)` (E) dissolves in warm conc. HCl to give a yellow solution (F). `iv)` With `H_(2)S`, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H). `v)` Solution (F) on treatment with thiocyanate ions gives blood red coloured compound (I). Identify the substances from (A) to (I). Yellow ppt (G) is a `:`A. metal sulphateB. metal sulphideC. metallic precipitateD. sulphur
A compound (A) is greenish crystalline salt which gave the following results `:` `i)` Addition of `BaCl_(2)` solution to solution of (A) results in the formation of a white ppt. (B), which is insoluble in dil. HCl. `ii)` On heating (A), water vapours and two oxides of sulphur, (C ) and (D) are liberated leaving a red brown residue (E). `iii)` (E) dissolves in warm conc. HCl to give a yellow solution (F). `iv)` With `H_(2)S`, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H). `v)` Solution (F) on treatment with thiocyanate ions gives blood red coloured compound (I). Identify the substances from (A) to (I). Red brown residue (E) produces metal when it is heated with I) coke`" "`II)`Al_(2)O_(3)` `III)` metal sulphide of same metal `IV)` Al metalA. I,IIB. I,IIIC. I,III,IVD. I,IV
A compound (A) is greenish crystalline salt which gave the following results `:` `i)` Addition of `BaCl_(2)` solution to solution of (A) results in the formation of a white ppt. (B), which is insoluble in dil. HCl. `ii)` On heating (A), water vapours and two oxides of sulphur, (C ) and (D) are liberated leaving a red brown residue (E). `iii)` (E) dissolves in warm conc. HCl to give a yellow solution (F). `iv)` With `H_(2)S`, the solution (F) yields a pale yellow ppt. (G), which when filtered, leaves a greenish filtrate (H). `v)` Solution (F) on treatment with thiocyanate ions gives blood red coloured compound (I). Identify the substances from (A) to (I). Yellow ppt (G) is a `:`A. `+3,+2,+2`B. `+3,+3,+2`C. `+2,+3,+2`D. `+2,+2,+3`
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `MnO_(4)^(2-)+H^(+)rarr" "(p)"`One of the products of transition element is paramagnetic.B. `Cu^(+)(aq)rarr " "(q)` Disproportation reaction.C. `Cr_(2)O_(7)^(2-)(s)+H^(+)("conc.")+Cl^(-)(s) rarr" "(r )` One of the products central atom exhibits its highest oxidation stateD. `Fe_(2)(SO_(4))_(3)+I^(-)rarr" "(s)` In one of the products central atom exhibits its highest oxidation stat
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `O_(2)^(-)rarrO_(2)+O_(2)^(2)" "(p)` redox reactionB. `CrO_(4)^(2-)+H^(+)rarr" "(q)` One of the products has trigonal planar structureC. `MnO_(4)^(-)+NO_(2)^(-)+H^(+)rarr" "(r )` dimeric bridged tetrahdedral metal ionD. `NO_(3)^(-)+H_(2)SO_(4)+Fe^(2+)rarr" "(s)` disproportionation
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `O_(2)^(-)rarrO_(2)+O_(2)^(2-)" "(p)` redox reactionB. `CrO_(4)^(2-)+H^(+)rarr" "(q)` one of the products has trigonal planar structureC. `MnO_(4)^(-)+NO_(2)^(-)+H^(+)rarr" "(r) ` dimerica bridge tetrahdedral metal ionD. `NO_(3)^(-)+H_(2)SO_(4)+Fe^(2+)rarr" "(s)` disproportionation
Match the reactions in Column I with nature of the reactions `//` type of the products in Column II. A. `MnO_(4)^(2-)+H^(+)rarr" "(p)` One of the products of transition element is paramagneticB. `Cu^(+)(aq)rarr" "(q)` Disproportionation reaction.C. `Cr_(2)O_(7)^(2-)(s)+H^(+)("conc.")+Cl^(-)(s)" "(r)` One of the products is liberated as coloured vapours.D. `Fe_(2)(SO_(4))_(3)+I^(-)rarr" "(s)` In one of the products central atom exhibits its highest oxidation state.
When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous `NaCl` to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The compound N isA. `AgNO_(3)`B. `Zn(NO_(3))_(2)`C. `Al(NO_(3))_(2)`D. `Pb(NO_(3))_(2)`
When a metal rod M is dipped into an aqueous colourless concentrated solution of compound N, the solution turns light blue. Addition of aqueous NaCl to the blue solution gives a white precipitate O. Addition of aqueous `NH_(3)` dissolves O and gives an intense blue solution. The metal rod M isA. FeB. CuC. NiD. CO

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment