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`CH_(3)OC_(2)H_(5)` and `(CH_(3))_(3)COCH_(3)` are treated with hydroiodic acid. The fragments after reaction obtained areA. `CH_(3)I+C_(2)H_(5)OH,(CH_(3))_(3)C-I+CH_(3)OH`B. `CH_(3)OH+C_(2)H_(5)I,(CH_(3))_(3)C-I+CH_(3)OH`C. `CH_(3)OH+C_(2)H_(5)I,(CH_(3))_(3)C-OH+CH_(3)I`D. `CH_(3)I+C_(2)H_(5)OH,CH_(3)I+(CH_(3))_(3)C-OH.` |
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Answer» Correct Answer - A In `CH_(3)OC_(2)H_(5)`. Attack of `I^(-)` ion occurs at `CH_(3)` group giving `CH_(3)I and C_(2)H_(5)OH.` However, in `(CH_(3))_(3)COCH_(3),` the reaction proceeds by `S_(N^(1))` mechanism and `I^(-)` ion attack more stble `(CH_(3))_(3)C^(+)` ion giving `(CH_(3))_(3)CI and CH_(3)OH`. |
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