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Calculate the ration of speed of sound in neon to that in water vapours at any temperature. Molecular weight on neon `=2.02xx10^(-2)kg//mol e` and for water vapours, molecular weight is `1.8xx10^(-2)kg//mol e`. |
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Answer» Here, `M_(n)=2.02xx10^(-2)kg//mol e` `M_(w)=1.8xx10^(-2)kg//m ol e` As neon is monoatomic, therefore `gamma_(n)=5//3` and water vapours are non-linear triatomic. `:. Gamma_(w)=4//3` As `upsilon=sqrt((gammarho)/(rho))=sqrt((gamma RT)/(M))` and T is same, therefore, `(upsilon_(n))/(upsilon_(w))=sqrt((gamma_(n))/(M_(n))xxM_(w)/(gamma_(w)))=(5//3xx1.8xx10^(-2))/(2.02xx10^(-2)xx4//3)` `=sqrt((5xx18)/(2.02xx4))=sqrt((9)/(8.08))=sqrt(1.1138)` `(upsilon_(n))/(upsilon_(w))=1.055` |
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